游戏中有一需求，就是一个矩形或者Cube绕着某一点旋转任意角度，现在给出下面算法。

public static Vector3 RotateRound(Vector3 position, Vector3 center, Vector3 axis, float angle)  {    Vector3 point = Quaternion.AngleAxis(angle, axis) * (position - center);    Vector3 resultVec3 = center + point;    return resultVec3;  }

测试用例

using UnityEngine;using System.Collections; public class RotateTest : MonoBehaviour {  public LineRenderer line1;  public LineRenderer line2;  public float angle = 30f;    private Vector3 v0;  private Vector3 v1;  private Vector3 v2;  private Vector3 v3;  private Vector3 v4;  private Vector3 vCenter;  void Start()  {    v0 = new Vector3(3f,0f,1f);    v1 = new Vector3(1f, 0f, 3f);    v2 = new Vector3(4f, 0f, 6f);    v3 = new Vector3(6f, 0f, 4f);    vCenter = new Vector3(2f, 0f, 2f);  }  // Use this for initialization void Update ()   {   line1.SetVertexCount(5);    line1.SetPosition(0,v0);    line1.SetPosition(1,v1);    line1.SetPosition(2,v2);    line1.SetPosition(3,v3);    line1.SetPosition(4,v0);     line2.SetVertexCount(5);    Vector3 v01 = MathUtils.RotateRound(v0, vCenter, Vector3.up, angle);    Vector3 v11 = MathUtils.RotateRound(v1, vCenter, Vector3.up, angle);    Vector3 v21 = MathUtils.RotateRound(v2, vCenter, Vector3.up, angle);    Vector3 v31 = MathUtils.RotateRound(v3, vCenter, Vector3.up, angle);    Vector3 v41 = MathUtils.RotateRound(v4, vCenter, Vector3.up, angle);    line2.SetPosition(0, v01);    line2.SetPosition(1, v11);    line2.SetPosition(2, v21);    line2.SetPosition(3, v31);    line2.SetPosition(4, v01); }}