如果有一个字符串 eg: "sun,star,moon,clouds",想要在MS SQL中根据给定的分隔符','把这个字符串分解成各个元素[sun] [star] [moon] [clouds]，如何实现呢？为此，创建一个Function,代码如下:复制代码 代码如下: CREATE FUNCTION [dbo].[Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) RETURNS @temptable TABLE (items VARCHAR(8000)) AS BEGIN DECLARE @idx INT DECLARE @slice VARCHAR(8000) SELECT @idx = 1 IF len(@String)<1 OR @String IS NULL RETURN while @idx!= 0 BEGIN SET @idx = charindex(@Delimiter,@String) IF @idx!=0 SET @slice = LEFT(@String,@idx - 1) ELSE SET @slice = @String IF(len(@slice)>0) INSERT INTO @temptable(Items) VALUES(@slice) SET @String = RIGHT(@String,len(@String) - @idx) IF len(@String) = 0 break END RETURN END

示例：如果输入 SELECT * FROM dbo.Split_StrByDelimiter('sun,star,moon,clouds',',') 结果返回 sun star moon clouds 在上面的代码做变形，返回有多少个元素复制代码 代码如下: CREATE FUNCTION [dbo].[GetCount_Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) RETURNS INT AS BEGIN DECLARE @temptable TABLE (items VARCHAR(8000)) DECLARE @SplitCount INT DECLARE @idx INT DECLARE @slice VARCHAR(8000) SELECT @idx = 1 IF len(@String)<1 OR @String IS NULL RETURN 0 while @idx!= 0 BEGIN SET @idx = charindex(@Delimiter,@String) IF @idx!=0 SET @slice = LEFT(@String,@idx - 1) ELSE SET @slice = @String IF(len(@slice)>0) INSERT INTO @temptable(Items) VALUES(@slice) SET @String = RIGHT(@String,len(@String) - @idx) IF len(@String) = 0 break END SET @SplitCount=(SELECT COUNT(*) FROM @temptable) RETURN @SplitCount END

示例 SELECT dbo.GetCount_Split_StrByDelimiter('sun,star,moon,clouds',',') 结果返回 4