1.如果有ID字段，就是具有唯一性的字段复制代码 代码如下: delect table where id not in ( select max(id) from table group by col1,col2,col3... )

group by 子句后跟的字段就是你用来判断重复的条件，如只有col1，那么只要col1字段内容相同即表示记录相同。 2. 如果是判断所有字段也可以这样复制代码 代码如下: select * into #aa from table group by id1,id2,.... delete table insert into table select * from #aa

3. 没有ID的情况复制代码 代码如下: select identity(int,1,1) as id,* into #temp from tabel delect # where id not in ( select max(id) from # group by col1,col2,col3...) delect table inset into table(...) select ..... from #temp

4. col1+','+col2+','...col5 联合主键复制代码 代码如下: select * from table where col1+','+col2+','...col5 in ( select max(col1+','+col2+','...col5) from table where having count(*)>1 group by col1,col2,col3,col4 )

group by 子句后跟的字段就是你用来判断重复的条件，如只有col1，那么只要col1字段内容相同即表示记录相同。 5.复制代码 代码如下: select identity(int,1,1) as id,* into #temp from tabel select * from #temp where id in ( select max(id) from #emp where having count(*)>1 group by col1,col2,col3...)

6.复制代码 代码如下: select distinct * into #temp from tablename delete tablename go insert tablename select * from #temp Sqlclub go drop table #temp