l 函数语法:reduce(function, iterable[, initializer])
l 返回值:计算结果的
实例代码演示:
import functools l = [1, 2, 3, 4, 5] product = functools.reduce(lambda x, y: x * y, l) product product = functools.reduce(lambda x, y: x + y, l)
返回结果:
reduce(lambda x,y: x*y,[1,2,3,4,5]) 120